x^2-60x+16=0

Solution for x^2-60x+16=0 equation:

x^2-60x+16=0

a = 1; b = -60; c = +16;
Δ = b2-4ac
Δ = -602-4·1·16
Δ = 3536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3536}=\sqrt{16*221}=\sqrt{16}*\sqrt{221}=4\sqrt{221}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{221}}{2*1}=\frac{60-4\sqrt{221}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{221}}{2*1}=\frac{60+4\sqrt{221}}{2}
$